On Tue, Nov 17, 2015 at 01:24:11PM +0300, Alexander Shiyan wrote: > Hello. > > barebox@/ # for i in /dev/* ; do echo $i; done > /dev/flash0 > /dev/full > /dev/m25p0 > /dev/m25p1 > /dev/mem > /dev/null > /dev/ram0 > /dev/self0 > /dev/serial1 > /dev/zero > > barebox@/ # for i in /dev/*1 ; do echo $i; done > /dev/m25p1 > /dev/serial1 > > barebox@/ # for i in /dev/*2 ; do echo $i; done > /dev/*2 > ^^^^^^^^ Is this correct? When there is no /dev/*2, then yes, this is correct. Try the same under bash, it behaves the same. If there's nothing matching the wildcard pattern then the wildcards are just passed through. Sascha -- Pengutronix e.K. | | Industrial Linux Solutions | http://www.pengutronix.de/ | Peiner Str. 6-8, 31137 Hildesheim, Germany | Phone: +49-5121-206917-0 | Amtsgericht Hildesheim, HRA 2686 | Fax: +49-5121-206917-5555 | _______________________________________________ barebox mailing list barebox@xxxxxxxxxxxxxxxxxxx http://lists.infradead.org/mailman/listinfo/barebox
