Re: [PATCH 2/2] sha1/sha256: use be32_to_cpu and cpu_to_be32

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On 09/24/2010 01:34 AM, Jean-Christophe PLAGNIOL-VILLARD wrote:
On 09:43 Fri 24 Sep     , Sascha Hauer wrote:
On Fri, Sep 24, 2010 at 12:00:42AM -0700, Andre wrote:
On 09/21/2010 06:28 AM, Jean-Christophe PLAGNIOL-VILLARD wrote:

Signed-off-by: Jean-Christophe PLAGNIOL-VILLARD<plagnioj at jcrosoft.com>
---
   lib/sha1.c   |   20 +++-----------------
   lib/sha256.c |   19 +++----------------
   2 files changed, 6 insertions(+), 33 deletions(-)

diff --git a/lib/sha1.c b/lib/sha1.c
index 0e8aed1..b4e2abc 100644
--- a/lib/sha1.c
+++ b/lib/sha1.c
@@ -29,6 +29,7 @@
   #include<digest.h>
   #include<init.h>
   #include<linux/string.h>
+#include<asm/byteorder.h>

   #define SHA1_SUM_POS	-0x20
   #define SHA1_SUM_LEN	20
@@ -44,23 +45,8 @@ sha1_context;
   /*
    * 32-bit integer manipulation macros (big endian)
    */
-#ifndef GET_UINT32_BE
-#define GET_UINT32_BE(n,b,i) {				\
-	(n) = ( (uint32_t) (b)[(i)    ]<<   24 )	\
-	    | ( (uint32_t) (b)[(i) + 1]<<   16 )	\
-	    | ( (uint32_t) (b)[(i) + 2]<<    8 )	\
-	    | ( (uint32_t) (b)[(i) + 3]       );	\
-}
-#endif
-
-#ifndef PUT_UINT32_BE
-#define PUT_UINT32_BE(n,b,i) {				\
-	(b)[(i)    ] = (unsigned char) ( (n)>>   24 );	\
-	(b)[(i) + 1] = (unsigned char) ( (n)>>   16 );	\
-	(b)[(i) + 2] = (unsigned char) ( (n)>>    8 );	\
-	(b)[(i) + 3] = (unsigned char) ( (n)       );	\
-}
-#endif
+#define GET_UINT32_BE(n,b,i) (n) = be32_to_cpu(((uint32_t*)(b))[i / 4])
+#define PUT_UINT32_BE(n,b,i) ((uint32_t*)(b))[i / 4] = cpu_to_be32(n)



The previous macros served two purposes: endian swapping and performing
the memory accesses byte-by-byte. New versions are unsafe for CPUs which
do not support misaligned 32bit memory accesses.

Indeed. We have get_unaligned_be32() / put_unaligned_be32(). These should be
the correct functions, right?
>
no-nned IIRC as be32_to_cpu and cpu_to_be32 already handle this
depending on the arch


I think get_unaligned_be32() / put_unaligned_be32() are correct in this case. be32_to_cpu / cpu_to_be32 perform endian swapping (if required) with source and destination both being 32bit variables, not memory locations ?

Of course the easy way to test any version is to build for an architecture which cares about alignment and look at the disassembly. If the compiler generates one 32bit load/store instruction instead of 4 byte accesses then the code is wrong.

In any case, this looks dubious:

#define PUT_UINT32_BE(n,b,i) ((uint32_t*)(b))[i / 4] = cpu_to_be32(n)

Behaviour when i == 0 is the same as when i == 1, which wasn't the case with the old macros. Also, if b is not 32bit aligned, store will be misaligned regardless of having cpu_to_be32(), or anything else, on the rhs.

Andre
--

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