On Fri, Jan 11, 2019 at 08:03:45AM +0000, Sietse van Zanen wrote: > Hi, > > > > I am writing a daemon script which uses sd_notify watchdog. This works fine, > system will kill the if the process doesn’t notify. > > > > However, I have seen in 1 occasion where, due to a programming error, the > script got stuck in a read and was not killed where it should have been. > > So my question is, what does systemd actually do when the watchdog expires, > which signal does it send? > It's well documented in the manpages. From systemd.service(5) under the description of WatchdogSec=: If the time between two such calls is larger than the configured time, then the service is placed in a failed state and it will be terminated with SIGABRT (or the signal specified by WatchdogSignal=) _______________________________________________ systemd-devel mailing list systemd-devel@xxxxxxxxxxxxxxxxxxxxx https://lists.freedesktop.org/mailman/listinfo/systemd-devel