From: Josef Bacik <josef@xxxxxxxxxxxxxx> commit 011b28acf940eb61c000059dd9e2cfcbf52ed96b upstream. This function has the following pattern while (1) { ret = whatever(); if (ret) goto out; } ret = 0 out: return ret; However several places in this while loop we simply break; when there's a problem, thus clearing the return value, and in one case we do a return -EIO, and leak the memory for the path. Fix this by re-arranging the loop to deal with ret == 1 coming from btrfs_search_slot, and then simply delete the ret = 0; out: bit so everybody can break if there is an error, which will allow for proper error handling to occur. CC: stable@xxxxxxxxxxxxxxx # 4.4+ Signed-off-by: Josef Bacik <josef@xxxxxxxxxxxxxx> Reviewed-by: David Sterba <dsterba@xxxxxxxx> Signed-off-by: David Sterba <dsterba@xxxxxxxx> Signed-off-by: Greg Kroah-Hartman <gregkh@xxxxxxxxxxxxxxxxxxx> --- fs/btrfs/tree-log.c | 13 +++++++------ 1 file changed, 7 insertions(+), 6 deletions(-) --- a/fs/btrfs/tree-log.c +++ b/fs/btrfs/tree-log.c @@ -1791,6 +1791,7 @@ static noinline int fixup_inode_link_cou break; if (ret == 1) { + ret = 0; if (path->slots[0] == 0) break; path->slots[0]--; @@ -1803,17 +1804,19 @@ static noinline int fixup_inode_link_cou ret = btrfs_del_item(trans, root, path); if (ret) - goto out; + break; btrfs_release_path(path); inode = read_one_inode(root, key.offset); - if (!inode) - return -EIO; + if (!inode) { + ret = -EIO; + break; + } ret = fixup_inode_link_count(trans, root, inode); iput(inode); if (ret) - goto out; + break; /* * fixup on a directory may create new entries, @@ -1822,8 +1825,6 @@ static noinline int fixup_inode_link_cou */ key.offset = (u64)-1; } - ret = 0; -out: btrfs_release_path(path); return ret; }