Re: [PATCH] powerpc: Fix a bug in __div64_32 if divisor is zero

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Le 20/08/2020 à 15:10, Guohua Zhong a écrit :
When cat /proc/pid/stat, do_task_stat will call into cputime_adjust,
which call stack is like this:

[17179954.674326]BookE Watchdog detected hard LOCKUP on cpu 0
[17179954.674331]dCPU: 0 PID: 1262 Comm: TICK Tainted: P        W  O    4.4.176 #1
[17179954.674339]dtask: dc9d7040 task.stack: d3cb4000
[17179954.674344]NIP: c001b1a8 LR: c006a7ac CTR: 00000000
[17179954.674349]REGS: e6fe1f10 TRAP: 3202   Tainted: P        W  O     (4.4.176)
[17179954.674355]MSR: 00021002 <CE,ME>  CR: 28002224  XER: 00000000
[17179954.674364]
GPR00: 00000016 d3cb5cb0 dc9d7040 d3cb5cc0 00000000 0000025d ffe15b24 ffffffff
GPR08: de86aead 00000000 000003ff ffffffff 28002222 0084d1c0 00000000 ffffffff
GPR16: b5929ca0 b4bb7a48 c0863c08 0000048d 00000062 00000062 00000000 0000000f
GPR24: 00000000 d3cb5d08 d3cb5d60 d3cb5d64 00029002 d3e9c214 fffff30e d3e9c20c
[17179954.674410]NIP [c001b1a8] __div64_32+0x60/0xa0
[17179954.674422]LR [c006a7ac] cputime_adjust+0x124/0x138
[17179954.674434]Call Trace:
[17179961.832693]Call Trace:
[17179961.832695][d3cb5cb0] [c006a6dc] cputime_adjust+0x54/0x138 (unreliable)
[17179961.832705][d3cb5cf0] [c006a818] task_cputime_adjusted+0x58/0x80
[17179961.832713][d3cb5d20] [c01dab44] do_task_stat+0x298/0x870
[17179961.832720][d3cb5de0] [c01d4948] proc_single_show+0x60/0xa4
[17179961.832728][d3cb5e10] [c01963d8] seq_read+0x2d8/0x52c
[17179961.832736][d3cb5e80] [c01702fc] __vfs_read+0x40/0x114
[17179961.832744][d3cb5ef0] [c0170b1c] vfs_read+0x9c/0x10c
[17179961.832751][d3cb5f10] [c0171440] SyS_read+0x68/0xc4
[17179961.832759][d3cb5f40] [c0010a40] ret_from_syscall+0x0/0x3c

do_task_stat->task_cputime_adjusted->cputime_adjust->scale_stime->div_u64
->div_u64_rem->do_div->__div64_32

In some corner case, stime + utime = 0 if overflow. Even in v5.8.2  kernel
the cputime has changed from unsigned long to u64 data type. About 200
days, the lowwer 32 bit will be 0x00000000. Because divisor for __div64_32
is unsigned long data type,which is 32 bit for powepc 32, the bug still
exists.

So it is also a bug in the cputime_adjust which does not check if
stime + utime = 0

time = scale_stime((__force u64)stime, (__force u64)rtime,
                 (__force u64)(stime + utime));

The commit 3dc167ba5729 ("sched/cputime: Improve cputime_adjust()") in
mainline kernel may has fixed this case. But it is also better to check
if divisor is 0 in __div64_32 for other situation.

Signed-off-by: Guohua Zhong <zhongguohua1@xxxxxxxxxx>
Fixes:14cf11af6cf6 "( powerpc: Merge enough to start building in arch/powerpc.)"
Fixes:94b212c29f68 "( powerpc: Move ppc64 boot wrapper code over to arch/powerpc)"
Cc: stable@xxxxxxxxxxxxxxx # v2.6.15+
---
  arch/powerpc/boot/div64.S | 4 ++++
  arch/powerpc/lib/div64.S  | 4 ++++
  2 files changed, 8 insertions(+)

diff --git a/arch/powerpc/boot/div64.S b/arch/powerpc/boot/div64.S
index 4354928ed62e..39a25b9712d1 100644
--- a/arch/powerpc/boot/div64.S
+++ b/arch/powerpc/boot/div64.S
@@ -13,6 +13,9 @@
.globl __div64_32
  __div64_32:
+	li	r9,0
+	cmplw	r4,r9	# check if divisor r4 is zero
+	beq	5f			# jump to label 5 if r4(divisor) is zero

In generic version in lib/math/div64.c, there is no checking of 'base' either.
Do we really want to add this check in the powerpc version only ?

The only user of __div64_32() is do_div() in include/asm-generic/div64.h. Wouldn't it be better to do the check there ?

Christophe


  	lwz	r5,0(r3)	# get the dividend into r5/r6
  	lwz	r6,4(r3)
  	cmplw	r5,r4
@@ -52,6 +55,7 @@ __div64_32:
  4:	stw	r7,0(r3)	# return the quotient in *r3
  	stw	r8,4(r3)
  	mr	r3,r6		# return the remainder in r3
+5:					# return if divisor r4 is zero
  	blr
/*
diff --git a/arch/powerpc/lib/div64.S b/arch/powerpc/lib/div64.S
index 3d5426e7dcc4..1cc9bcabf678 100644
--- a/arch/powerpc/lib/div64.S
+++ b/arch/powerpc/lib/div64.S
@@ -13,6 +13,9 @@
  #include <asm/processor.h>
_GLOBAL(__div64_32)
+	li	r9,0
+	cmplw	r4,r9	# check if divisor r4 is zero
+	beq	5f			# jump to label 5 if r4(divisor) is zero
  	lwz	r5,0(r3)	# get the dividend into r5/r6
  	lwz	r6,4(r3)
  	cmplw	r5,r4
@@ -52,4 +55,5 @@ _GLOBAL(__div64_32)
  4:	stw	r7,0(r3)	# return the quotient in *r3
  	stw	r8,4(r3)
  	mr	r3,r6		# return the remainder in r3
+5:					# return if divisor r4 is zero
  	blr




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