On 2017年01月24日 00:27, Peter Rosin wrote:
On 2017-01-23 11:40, Qi Hou wrote:
During stepping down the tree, parent node is gotten first and its refcount is
increased with of_node_get() in __of_get_next_child(). Since it just being used
as step node, its refcount must be decreased with of_node_put() after traversing
its child nodes.
Or, its refcount will never be descreased to ZERO, then it will never be freed,
as well as other related memory blocks.
To fix this, decrease refcount of parent with of_node_put() after
__of_find_node_by_path().
Signed-off-by: Qi Hou <qi.hou@xxxxxxxxxxxxx>
Acked-by: Peter Rosin <peda@xxxxxxxxxx>
---
drivers/of/base.c | 4 +++-
1 file changed, 3 insertions(+), 1 deletion(-)
diff --git a/drivers/of/base.c b/drivers/of/base.c
index d4bea3c..091ad29 100644
--- a/drivers/of/base.c
+++ b/drivers/of/base.c
@@ -842,8 +842,10 @@ struct device_node *of_find_node_opts_by_path(const char *path, const char **opt
if (!np)
np = of_node_get(of_root);
while (np && *path == '/') {
+ struct device_node *npp = np;
Hi,
You failed to add a blank line here...
Sorry, I miss it, I will add.
path++; /* Increment past '/' delimiter */
- np = __of_find_node_by_path(np, path);
+ np = __of_find_node_by_path(npp, path);
...and there's no need to change the above line if you
want to make a minimal change.
Just want the code readable, as npp is parent and np is a some child of
parent.
-- Best regards,
Qi Hou
Cheers,
peda
+ of_node_put(npp);
path = strchrnul(path, '/');
if (separator && separator < path)
break;
--
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