sparc is big-endian only but sparse assumes the same endianness as the building machine. This is problematic for code which expect __BYTE_ORDER__ being correctly predefined by the compiler which sparse can then pre-process differently from what gcc would, depending on the building machine endianness. Fix this by letting sparse know about the architecture endianness. To: David S. Miller <davem@xxxxxxxxxxxxx> CC: sparclinux@xxxxxxxxxxxxxxx Signed-off-by: Luc Van Oostenryck <luc.vanoostenryck@xxxxxxxxx> --- arch/sparc/Makefile | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/arch/sparc/Makefile b/arch/sparc/Makefile index a42aa114e..08d477faf 100644 --- a/arch/sparc/Makefile +++ b/arch/sparc/Makefile @@ -14,7 +14,7 @@ else KBUILD_DEFCONFIG := sparc64_defconfig endif -CHECKFLAGS += -D__sparc__ +CHECKFLAGS += -D__sparc__ -mbig-endian ifeq ($(CONFIG_SPARC32),y) ##### -- 2.14.0 -- To unsubscribe from this list: send the line "unsubscribe sparclinux" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html