Oleg Verych wrote:
+ uint32_t vx; + int dp; + + if (vhi) { + vx = vhi; + dp = 0; + } else { + vx = (uint32_t) v;`v' is a data in memory, accessed with 32-bits cast, thus operation yields high 32-bits part of `v'.
Bullsh*t. That would be *(uint32_t *)&v. Casting between integer types truncate the high bits regardless of platform endianness.
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