Re: [PATCH 1/3] libselinux: free empty scandir(3) result

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On Mon, 29 Apr 2024 at 22:35, William Roberts <bill.c.roberts@xxxxxxxxx> wrote:
>
> On Mon, Apr 29, 2024 at 11:39 AM Christian Göttsche
> <cgoettsche@xxxxxxxxxxxxx> wrote:
> >
> > From: Christian Göttsche <cgzones@xxxxxxxxxxxxxx>
> >
> > In case scandir(3) finds no entries still free the returned result to
> > avoid leaking it.
> >
> > Also do not override errno in case of a failure.
> >
> > Reported.by: Cppcheck
> >
> > Signed-off-by: Christian Göttsche <cgzones@xxxxxxxxxxxxxx>
> > ---
> >  libselinux/src/booleans.c | 6 +++++-
> >  1 file changed, 5 insertions(+), 1 deletion(-)
> >
> > diff --git a/libselinux/src/booleans.c b/libselinux/src/booleans.c
> > index c557df65..1ede8e2d 100644
> > --- a/libselinux/src/booleans.c
> > +++ b/libselinux/src/booleans.c
> > @@ -53,7 +53,11 @@ int security_get_boolean_names(char ***names, int *len)
> >
> >         snprintf(path, sizeof path, "%s%s", selinux_mnt, SELINUX_BOOL_DIR);
> >         *len = scandir(path, &namelist, &filename_select, alphasort);
> > -       if (*len <= 0) {
> > +       if (*len < 0) {
> > +               return -1;
> > +       }
> > +       if (*len == 0) {
>
> Changing this will allow scandir to fail and it continue, what's the point?

What do you mean by "continue"?
The function will still return -1 with errno set if scandir(3) returns
<= 0, like it does currently.
But currently if scandir() returns 0, we currently leak the pointer to
the empty array.

>
> > +               free(namelist);
> >                 errno = ENOENT;
> >                 return -1;
> >         }
> > --
> > 2.43.0
> >
> >





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