When the hash table slot array allocation fails in hashtab_init(),
h->size is left initialized with a non-zero value, but the h->htable
pointer is NULL. This may then cause a NULL pointer dereference, since
the policydb code relies on the assumption that even after a failed
hashtab_init(), hashtab_map() and hashtab_destroy() can be safely called
on it. Yet, these detect an empty hashtab only by looking at the size.
Fix this by making sure that hashtab_init() always leaves behind a valid
empty hashtab when the allocation fails.
Fixes: 03414a49ad5f ("selinux: do not allocate hashtabs dynamically")
Signed-off-by: Ondrej Mosnacek <omosnace@xxxxxxxxxx>
---
security/selinux/ss/hashtab.c | 17 ++++++++++++-----
1 file changed, 12 insertions(+), 5 deletions(-)
diff --git a/security/selinux/ss/hashtab.c b/security/selinux/ss/hashtab.c
index 727c3b484bd3..0ae4e4e57a40 100644
--- a/security/selinux/ss/hashtab.c
+++ b/security/selinux/ss/hashtab.c
@@ -31,13 +31,20 @@ static u32 hashtab_compute_size(u32 nel)
int hashtab_init(struct hashtab *h, u32 nel_hint)
{
- h->size = hashtab_compute_size(nel_hint);
+ u32 size = hashtab_compute_size(nel_hint);
+
+ /* should already be zeroed, but better be safe */
h->nel = 0;
- if (!h->size)
- return 0;
+ h->size = 0;
+ h->htable = NULL;
- h->htable = kcalloc(h->size, sizeof(*h->htable), GFP_KERNEL);
- return h->htable ? 0 : -ENOMEM;
+ if (size) {
+ h->htable = kcalloc(size, sizeof(*h->htable), GFP_KERNEL);
+ if (!h->htable)
+ return -ENOMEM;
+ h->size = size;
+ }
+ return 0;
}
int __hashtab_insert(struct hashtab *h, struct hashtab_node **dst,
--
2.33.1
