Are you invoking it with an argument?
If you are running it without an argument, referrencing argv[1] is not valid
since it goes beyond the limit of (argc -1). Remember argv[0] is the program
name and argc[1] is the first argument.
It runs ok for me with an argument, exiting with status 1 as expected.
Am I misunderstanding the question ?
On Wednesday 09 January 2002 16:08, David Correa wrote:
> On Tue, 8 Jan 2002, Trano wrote:
> > #include <stdio.h>
> >
> > int
> > main(int argc, char **argv)
> > {
> > char buf[100];
> > strcpy(buf, argv[1]);
> > exit(1);
> > }
>
> Hi,
>
> That code produces a "Segmentation fault (core dumped)"
> with gcc version 2.96.
>
> Also this one:
This also should give a SEGV since the parameters to strncpy are in the wrong
order. buf[] has not been properly terminated with '\0'. Can program args be
overwritten with strncpy? I'm not sure.
>
> On Wed, 9 Jan 2002, Kenny Colliander wrote:
> >#include <stdio.h>
> >int main(int argc, char **argv)
> >{
> > char buf[100+1]; // + NULL
> > strncpy(argv[1], buf, 100);
> > exit(1);
> >}
>
> Regards,
>
> David Correa RHCE CCNA
> http://www.linux-tech.com
>
>
>
>
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