Re: [rpm-list] Setting binary rpm name according to a condition

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Luciano Miguel Ferreira Rocha wrote:
On Wed, Oct 25, 2006 at 05:05:17PM +0200, Erez Zilber wrote:
Hi,

I still have some problems. Here's the piece of code that sets the name of the binary rpm:

if [ "%_vendor" = "suse" ] ; then
       my_build_name_fmt=suse_name
       echo "suse"
else if [ "%_vendor" = "redhat" ] ; then
       my_build_name_fmt=redhat-name
       echo "redhat"
else
       echo "This version is not supported"
fi
fi

%define _build_name_fmt $my_build_name_fmt.%_arch.rpm
echo "_build_name_fmt = %_build_name_fmt"

When I run it, it does print the _build_name_fmt that I expect to see:
+ echo '_build_name_fmt = suse_name.x86_64.rpm'
_build_name_fmt = suse_name.x86_64.rpm

However, later it prints the following:
Wrote: /usr/src/packages/RPMS/$my_build_name_fmt.x86_64.rpm

Why doesn't it treat my_build_name_fmt as a variable?

I don't know if rpmbuild parses $ in all its steps.

Call it like this instead:

rpmbuild package.spec --define "_build_name_fmt $my_build_name_fmt.%_arch.rpm"

But $my_build_name_fmt gets its value in run-time. You can see that in the code piece above. How should that work?

Thanks,
--

____________________________________________________________

Erez Zilber | 972-9-971-7689

Software Engineer, Storage Team

Voltaire – _The Grid Backbone_

__

www.voltaire.com <http://www.voltaire.com/>



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