Move -lfun to the end of the command line. Jon ---- Learn to program using Linux assembly language http://www.cafeshops.com/bartlettpublish.8640017 On Tue, 4 Jan 2005, exits funnel wrote: > Hello, > > I've got the following simple source files: > > //Begin fun1.cpp > #include <iostream.h> > void fun1( ) { cout << "Exits in fun1( )\n"; } > //End fun1.cpp > > //Begin fun2.cpp > #include <iostream.h> > void fun2( ) { cout << "Exits in fun2( )\n"; } > //End fun2.cpp > > //Begin funmain.cpp > #include <iostream.h> > void fun1( ); > int main( ) > { > cout << "about to call fun1( )\n"; > fun1( ); > cout << "just called fun1( )\n"; > return 0; > } > //End funmain.cpp > > all of the source files are in the directory > /home/exits/moment/cpptest. I compile the two > functions like this: > > g++ -c fun1.cpp > g++ -c fun2.cpp > > I then archive the two resulting object files like > this: > > ar -cr libfun.a fun1.o fun2.o > > So far so good (I think) i've not got my library > containing the two functions. I can't seem to figure > out though how to link my main method agains the > archive. It seems this should work: > > g++ -o fun -L/home/exits/moment/cpptest -lfun > funmain.cpp > > but it doesn't instead g++ complains about an > undefined reference to fun1( ). If I just pop the .o > file on the command line when I compile/link main > everything is fine but I really need to get the > library stuff working. If anyone could point out what > I've done wrong, I'd really appreciate it. Thanks in > advance! > > -exits > > > > > __________________________________ > Do you Yahoo!? > Yahoo! Mail - You care about security. So do we. > http://promotions.yahoo.com/new_mail > > _______________________________________________ > Redhat-devel-list mailing list > Redhat-devel-list@xxxxxxxxxx > https://www.redhat.com/mailman/listinfo/redhat-devel-list > _______________________________________________ Redhat-devel-list mailing list Redhat-devel-list@xxxxxxxxxx https://www.redhat.com/mailman/listinfo/redhat-devel-list
