First tip for my question reference: http://www.softpanorama.org/Scripting/Shellorama/bash_debugging.shtml ### debecho (debug-echo), by Stefano Falsetto ### ### Will echo passed parameters only if DEBUG is set to a value. ### debecho () { if [ ! -z "$DEBUG" ]; then echo "$1" >&2 # ^^^ to stderr fi } DEBUG=on Whatever=whatnot debecho $Whatever # whatnot DEBUG= Whatever=notwhat debecho $Whatever # (Will not echo.) something better??? ;-) ESG 2009/5/4 ESGLinux <esggrupos@xxxxxxxxx> > Hello all > > this is a question about debuging bash scripts. I think this is a semi off > topic because its not a red hat question ... but I´m sure all of us have an > answer to this question. > > I have several scripts with echo commands to check variable values > > the code I use is like this > > if [ ! -z $DEBUG ]; then > echo "variable: $variable" > fi > > thus If I set DEBUG=on I get a lot messages with the variable values. > > My question is if is there any tip to do this without using the if code > snipet (something like an inline function...) > > on the other hand any tip about debugging bash scripts is welcome (like > setting option flags -n, -v o -x) > > Greetings > > ESG > > > -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subjecthttps://www.redhat.com/mailman/listinfo/redhat-list
