> -----Original Message----- > From: redhat-list-bounces@xxxxxxxxxx > [mailto:redhat-list-bounces@xxxxxxxxxx] On Behalf Of Bliss, Aaron > Sent: Tuesday, June 27, 2006 11:03 AM > To: redhat-list@xxxxxxxxxx > Subject: RE: Quick question on awk usage > > Sorry, $14 == 528, not $12 (looks like the email client > wrapped the line > also) > > Aaron > > Hi everyone, I have a quick question on using awk from the > command line; I have a tab delimited file, and would like to > know the syntax to print the entire line only when $12 == > 575; the syntax from the command line to print only $1 would > be cat security.log | awk '{print $1}' ; any ideas (grepping > for 578 won't be good enough since it's possible that > 578 could appear somewhere else in the file) Thanks very much. > > Aaron > > Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4 > Security 263985 Sun Jun 25 15:54:02 2006 528 > Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4 > Security 263985 Sun Jun 25 15:54:02 2006 575 > > I believe this should do it: awk ' $14 == 575 {print $0}' Michael -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
