Hi everyone, I have a quick question on using awk from the command line;
I have a tab delimited file, and would like to know the syntax to print
the entire line only when $12 == 575; the syntax from the command line
to print only $1 would be cat security.log | awk '{print $1}' ; any
ideas (grepping for 578 won't be good enough since it's possible that
578 could appear somewhere else in the file) Thanks very much.
Aaron
Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4
Security 263985 Sun Jun 25 15:54:02 2006 528
Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 4
Security 263985 Sun Jun 25 15:54:02 2006 575
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