I'm not sure how bash does it, but in perl the answer would be that your variable is lexically scoped inside the loop. Try declaring R at the beginning of the script. -G Regards, Gavin McDonald ======================== EVI Logistic Enterprises email: me@xxxxxxxxxxxx phone: (604) 313-3845 > -----Original Message----- > From: redhat-list-bounces@xxxxxxxxxx [mailto:redhat-list- > bounces@xxxxxxxxxx] On Behalf Of Magnus Andersen > Sent: Wednesday, January 04, 2006 12:05 PM > To: General Red Hat Linux discussion list > Subject: Script help needed... > > Hi All, > > I'm writing a script that I am going to use to test write data to an nfs > mount. I'm having problem with a variable. The variable R is set inside > a > while loop and it is null outside the loop even after it is set. > > Here is a code snippet. I've attached the whole script if anyone would > like > to look at the whole thing. > > if [ ! -f $PIDFILE ]; then > touch $PIDFILE > else > # Read PIDFILE and determine if script is already running. > cat $PIDFILE | while read LINE > do > if [ -z "$LINE" ]; then > break > else > #Get PID from PIDFILE > OLDPID=`echo $LINE | awk '{ print $1 }'` > RUNNING=`ps aux | grep $OLDPID | grep -v grep | wc -l | tr -d > ' > '` > if [ $RUNNING = 0 ]; then > R=0 > else > (( R = $R + 1 )) > echo $R > LOC=`echo $LINE | awk '{ print $2 }'` > fi > fi > done > fi > echo "R = $R" > > The last echo is null even after R is set inside the loop and I don't > understand why. > > Thanks, > > -- > Magnus Andersen > Systems Administrator / Oracle DBA > Walker & Associates, Inc. -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
