(Cc-ed to list in case anyone is interested) --On Thursday, October 13, 2005 4:08 PM -0300 "Shaw, Marco" <Marco.Shaw@xxxxxxxxx> wrote:
If I may, how did you get that tree view of the state of memory? By hand? From knowledge & experience? Thanks, Marco
Err... yes. Basically "by hand". It's a perl program I did while trying to understand the output of free(1) and the values found in /proc (I used the O'Reilly book on /proc and the one on the Kernel). Some things I never got sorted out completely. Sounds like cosmology:
Why is "sum(RSS)" != "Mapped memory" ? Why is "floating" (a correction) not exactly 0 (it used to be under 2.2
kernel I think)
Are 'slab' and 'page tables' correctly grouped under 'allocated'? Is the 'page cache' indeed the cache used for page I/O? Is the 'buffer cache' indeed the cache used for disk I/O?
As I'm not exactly 100% sysop, I gave up once I had satisficing results. It's nothing complicated anyway - here it is: <http://misato.m-plify.net/parse_free.pl> Best regards, -- David -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
