Or you could use grep truc /etc/hosts | cut -c1-15 -----Original Message----- From: redhat-list-bounces@xxxxxxxxxx [mailto:redhat-list-bounces@xxxxxxxxxx]On Behalf Of Benjamin J. Weiss Sent: Monday, January 03, 2005 2:38 PM To: General Red Hat Linux discussion list Subject: Re: Script truc nguyen wrote: >Hi, > >In my hosts file, the last line is as follow >197.2.23.134 truc TRUC > >I want to write a script to get the this IP address. >What command in sed or awk to execute this ? > >Thank you so much > > > I see that you've gotten a couple of answers already. However, in the interests of "There's more than one way to do it", here's another approach: grep truc /etc/hosts | grep -o "[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}\.[0-9]\{1,3\}" or grep truc /etc/hosts | grep -o "[0-9]*\.[0-9]*\.[0-9]*\.[0-9]*" or grep truc /etc/hosts | cut -f1 -d" " I'm sure that there are others. :) Ben -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
