ok - nobody.. so here is what i think and please correct me if I'm wrong: bs=1024 - this would be the size of each block in bytes count=2097152 the number if 1024 byte sized blocks in 2 gigs 1 gig is 1,073,741,824 bytes. divided by 1024 bytes/block i get 1048576 blocks - for 1 gig. so for 2 gigs it'll be 2097152 blocks. does this logic make sense? thanks... > hi all... this is probably a stupid question but anyway.. > > i want to add a swap file to my system. following the rule of 2 to 1 the > file would need to be 2 gigs because the ram is a gig. but using the dd > command what do i put for bs and count? > i was looking around on google but couldn't exactly find it.. > > thanks a lot... > > > > -- > Software is like sex: It's better when it's free. (Linus Torvalds) > > > -- > redhat-list mailing list > unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe > https://www.redhat.com/mailman/listinfo/redhat-list > -- Software is like sex: It's better when it's free. (Linus Torvalds) -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
