>I need some help and thought someone on this list might know. I am trying >to do some scripting but am running into the following problem: > >I have a file that contains a bunch of the following entries: > >trusty.F.0038 02/11/02 >trusty.F.0058 04/11/04 >trusty.F.0063 05/12/02 >trusty.F.0064 05/13/02 >trusty.F.0178 04/21/04 >trusty.F.0183 09/30/02 >trusty.F.0276 04/04/04 >..... > >I would like to take out entries that match 04/xx/04 (xx does not matter) >and dump them to a different file. In this case 58, 178 and 276. I am >unable to do this with awk. Anyone know of a way I can do this using >csh?? An extremely simple two line command line is: grep 04/../04 filename > file_with_04 grep -v 04/../04 filename > file_without_04 Awk can be used a well. You just use an if statement that looks for the string "04/" AND the string "/04" in field $2. If both are found output $0 into the with file, else output the line into the without file. Rather simple, really. MB -- e-mail: vidiot@xxxxxxxxxx /~\ The ASCII \ / Ribbon Campaign [So it's true, scythe matters. Willow 5/12/03] X Against Visit - URL: http://vidiot.com/ / \ HTML Email -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list