Hi All, I'm wondering if there is any way to have a setuid login script? Here's what I'm attempting to do: Have a user login via ssh to the system and when properly authenticated run the setuid binary. The binary runs fine if the user is already logged into a valid shell but if I set the binary to be the login shell then sshd(pam_unix) complains that the user is unknown: Mar 4 10:14:12 n1-22 sshd(pam_unix)[5074]: check pass; user unknown Mar 4 10:14:20 n1-22 sshd(pam_unix)[5074]: 1 more authentication failure; logname= uid=0 euid=0 tty=NODEVssh ruser= rhost=MYOTHERHOST My question is: Is there anyway around this? I understand the potential danger of setuid programs but still need to get this working :-) Thanks, Harry -- Harry Hoffman hhoffman@xxxxxxxxxxxxxxxx ---------------------------------------------------------------------------------- radical: 1) Someone waiting in line to become "The Establishment" ------------------------------------------------- This mail sent through IpSolutions: http://www.ip-solutions.net/ -- redhat-list mailing list unsubscribe mailto:redhat-list-request@xxxxxxxxxx?subject=unsubscribe https://www.redhat.com/mailman/listinfo/redhat-list
