Not being particularly resourceful with bourne or bash scripting,
my answer would be that this would be easiest with perl using a
hash.
something like:
my %count;
open( IN, "< yourfile" );
while( <IN> ) {
$count{$_}++;
}
close( IN );
foreach my $key( sort keys %count ) {
print "$key - $count{$key}\n";
}
-Steve
> -----Original Message-----
> From: redhat-list-admin@xxxxxxxxxx
> [mailto:redhat-list-admin@xxxxxxxxxx]On Behalf Of Mike Vanecek
> Sent: Tuesday, November 25, 2003 1:01 PM
> To: redhat_list
> Subject: group by & count command?
>
>
> I have a bash command that is essentially grep | sed | sort.
> It creates a file
> of sorted records. What I would like to do next is create a
> report that lists
> each unique item and its count.
>
> 1
> 1
> 1
> 2
> 3
> 3
>
> would be
> 1 - 3
> 2 - 1
> 3 - 2
>
> Can this be done via a bash command and if yes, how?
> Otherwise, I would assume
> it needs to be fed to a perl script?
>
> Thanks.
>
>
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