On Mon, Feb 22, 2021 at 11:21:04AM +0100, Sebastian Andrzej Siewior wrote:
> On 2021-02-19 10:33:36 [-0800], Paul E. McKenney wrote:
> > For definiteness, here is the first part of the change, posted earlier.
> > The commit log needs to be updated. I will post the change that keeps
> > the tick going as a reply to this email.
> …
> > diff --git a/kernel/softirq.c b/kernel/softirq.c
> > index 9d71046..ba78e63 100644
> > --- a/kernel/softirq.c
> > +++ b/kernel/softirq.c
> > @@ -209,7 +209,7 @@ static inline void invoke_softirq(void)
> > if (ksoftirqd_running(local_softirq_pending()))
> > return;
> >
> > - if (!force_irqthreads) {
> > + if (!force_irqthreads || !__this_cpu_read(ksoftirqd)) {
> > #ifdef CONFIG_HAVE_IRQ_EXIT_ON_IRQ_STACK
> > /*
> > * We can safely execute softirq on the current stack if
> > @@ -358,8 +358,8 @@ asmlinkage __visible void __softirq_entry __do_softirq(void)
> >
> > pending = local_softirq_pending();
> > if (pending) {
> > - if (time_before(jiffies, end) && !need_resched() &&
> > - --max_restart)
> > + if (!__this_cpu_read(ksoftirqd) ||
> > + (time_before(jiffies, end) && !need_resched() && --max_restart))
> > goto restart;
>
> This is hunk shouldn't be needed. The reason for it is probably that the
> following wakeup_softirqd() would avoid further invoke_softirq()
> performing the actual softirq work. It would leave early due to
> ksoftirqd_running(). Unless I'm wrong, any raise_softirq() invocation
> outside of an interrupt would do the same.
>
> I would like PeterZ / tglx to comment on this one. Basically I'm not
> sure if it is okay to expect softirqs beeing served and waited on that
> early in the boot.
>
The ksoftirqd threads get spawned during early_initcall() phase. Why not
just spawn them one step earlier what is totally safe? I mean before
do_pre_smp_initcalls() that calls early callbacks.
+ spawn_ksoftirqd();
rcu_init_tasks_generic();
do_pre_smp_initcalls();
With such change the spawning will not be depended on linker/compiler
i.e. when and in which order an early_initcall(spawn_ksoftirqd) callback
is executed.
--
Vlad Rezki
