Hi,
Is there an easy way to work out what offset into /dev/md3 would
correspond to LBA 3141211755 on /dev/sdc?
$ sudo fdisk -u -l /dev/sdc
Disk /dev/sdc: 1.8 TiB, 2000398934016 bytes, 3907029168 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disklabel type: gpt
Disk identifier: A9D7DEE3-9894-4D43-92D0-F5CC3B6E9E2A
Device Start End Sectors Size Type
/dev/sdc1 2048 1050623 1048576 512M Linux RAID
/dev/sdc2 1050624 7342079 6291456 3G Linux RAID
/dev/sdc3 7342080 9439231 2097152 1G Linux swap
/dev/sdc4 9439232 3907022847 3897583616 1.8T Linux RAID
/dev/sdc128 3907022848 3907029134 6287 3.1M BIOS boot
$ cat /proc/mdstat
Personalities : [linear] [multipath] [raid0] [raid1] [raid6] [raid5] [raid4] [raid10]
md3 : active raid10 sdc4[4] sdb4[3] sda4[0]
2922991104 blocks super 1.2 512K chunks 2 far-copies [3/3] [UUU]
bitmap: 0/22 pages [0KB], 65536KB chunk
An easier way than, "read the source," that is, the understanding
of which is a bit beyond me!
So it seems that is 3141211755 - 9439232 = 3131772523 sectors in to
device member sdc4, but md3 is a 3 device RAID-10 with far layout.
Cheers,
Andy
