On 19/12/13 08:12, Wilson Jonathan wrote:
I realise if it is possible its not going to be the best solution, but a
temp stop gap...
What I am thinking of doing is while I save up to by my 4'th new disk
for a new raid 6 setup (4 drive raid 6, currently has 3 disks 1 missing)
is it possible to use 3 existing smaller disks, create a raid0 across
them and then add the resulting /dev/dmX as "a disk" where the currently
missing disk is marked as missing.
EG. /dev/md7 ... /dev/sdb1 /dev/sdc1 /dev/sdd1 missing
mdadm create /dev/md8 raid0 /dev/sde1 /dev/sdf1 /dev/sdg1
mdadm --add /dev/md7 /dev/md8
Yes, this is possible, MD doesn't care what the block device is.... MD
uses block devices, and produces block devices...
If it is possible do I need to make sure the order in the conf file
first lists the /md8 then the /md7 or will mdadm see that a raid
contains a raid as a disk and then waits for it before assembling.
This might depend on what distribution you use /etc... IMHO, it should
work without a problem, but you should try it to confirm that.
IMHO, this isn't such a terrible idea, it adds at least some level of
protection, although if you can using a 4th smaller disk with RAID5
would be better still. I'm also assuming performance is not a critical
factor in all this...
BTW, can anyone comment whether this would work:
Using linear, then only the portion of the RAID0 with the failed disk
will be failed in the RAID6, so 2/3rds will still be 4 disk RAID6 and
1/3rd will be 3 disk RAID6?
Regards,
Adam
--
Adam Goryachev Website Managers www.websitemanagers.com.au
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