Re: Bug or not? Same array reports different/transformed UUID depending on check-method used.

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On Fri, Jun 17, 2011 at 09:29:49AM -0700, jeffs_linux@xxxxxxxxxxx wrote:
I suppose I should split this into its own thread rather than burying it
in my other.

Question first:

 I have two arrays attached to my Linux box.  Two methods of checking
 for arrays UUIDs give different results.  Why, and can I reply on
 these arrays?

Details follow:

Checking with,

mdadm --incremental --rebuild-map
I don't think this is a valid method for checking array uuid.

cat /dev/.mdadm/map
 md126 0.90 52f5b43c:e83f7e2a:be6ad32e:0536ab0e /dev/md/0_0
 md127 1.2  79fb7ad4:289bfae5:86c535ff:202960f2 /dev/md127

Staring at those UUIDs, I notice that one array's UUIDs match exactly
for the two methods of checking,

/dev/.mdadm/map       /dev/md/0_0  52f5b43c:e83f7e2a:be6ad32e:0536ab0e
mdadm --detail --scan /dev/md/0_0  52f5b43c:e83f7e2a:be6ad32e:0536ab0e

but the OTHER array's two UUIDs

/dev/.mdadm/map       /dev/md127   79fb7ad4:289bfae5:86c535ff:202960f2
mdadm --detail --scan /dev/md127   d47afb79:e5fa9b28:ff35c586:f2602920

are 'transforms' of one another; e.g.,
...
Why are /dev/md127's UUIDs, unlike /dev/md/0_0's, reporting mis-matched
& 'transformed'?

mdadm internally stores an uuid as an array of four 32bit integers
on disk it is different.
superblock version 0 (md0_0) stores 4 32bit values in host endian order(*)
(little-endian on x86)
superblock version 1 (md127) stores 16 8bit values in human readable
format (humans at least in western world countries are big endian)

The map_file, on the contrary, is always read and written as 4 32bit
values in host endian order, so on x86 machines you will find it
swapped.

Summary: the mapfile is for mdadm internal use only, use mdadm commands
(--detail, --examine) to obtain data.

(*) http://en.wikipedia.org/wiki/Endianness


L.

--
Luca Berra -- bluca@xxxxxxxxxx
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