I recently did a project which monitor raids event in system.
I used this way:
while(1){
open(/proc/mdstat);
poll();
do-something
close
}
I wanted to monitor all events in times.Supposing events A--10s-->B---1hour---->C,do-somethings taks 30s.
First I must fetch the event A.But I do do-somthing using 30s,so I did not monitor event B.
But the interval of B and C is 1 hour,so I only after 1 hours can detected the events B.
I can modified the do-something in order to reduce times.But in theory,I can omit event.
so I think modified kernel function mdstat_poll:
diff --git a/drivers/md/md.c b/drivers/md/md.c
index 39b27c4..aaecc03 100644
--- a/drivers/md/md.c
+++ b/drivers/md/md.c
@@ -6539,8 +6539,10 @@ static unsigned int mdstat_poll(struct file *filp, poll_table *wait)
/* always allow read */
mask = POLLIN | POLLRDNORM;
- if (mi->event != atomic_read(&md_event_count))
+ if (mi->event != atomic_read(&md_event_count)){
+ mi->event = atomic_read(&md_event_count);
mask |= POLLERR | POLLPRI;
+ }
return mask;
}
user space function like this:
opne(/proc/mdstat)
while(1){
poll
do-something
}
close
2011-06-02
majianpeng
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