On Thu, Jun 10, 2010 at 03:21:27PM -0700, Drew wrote: > In this case, you're parity blocks will actually be identical to your > non-parity blocks. This is because P1 is calculated as P1 = A1 XOR ?? > Since there is no other block to XOR your bits with, md falls back to > ?? = 0, and we all know that the XOR of 0 is the identity. That is, P1 > = A1 XOR 0 == A1 I'm curious whether md actually computes the XOR or has a shortcut path for the case where n=2. > I stand corrected. :-) No problem ;-) Gilad -- To unsubscribe from this list: send the line "unsubscribe linux-raid" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
