Re: RAID-6: help wanted

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Guy wrote:
Could you translate this into English?
P' = P + D_n + D_n'
Q' = Q + g^n * D_n + g^n * D_n'

I understand this much:
P    =old parity
D_n  =old data block(s)
P'   =new parity
D_n' =new data block(s)

But is "+" = xor?

I am lost on this one:
Q' = Q + g^n * D_n + g^n * D_n'

With the parity (xor) it can be done by the bit, so an example is easy.
Can Q be done by the bit, and if so, could you give an example?

If it takes more than 10 minutes, just tell me it is magic! :)

See my paper on the subject:

http://www.kernel.org/pub/linux/kernel/people/hpa/raid6.pdf

Also, on a related subject....
I have a 14 disk RAID5 with 1 spare.
Once RAID6 seems safe and stable I had hoped to convert to a 15 disk RAID6.
Is 15 disks too much for RAID6?
Any idea what a reasonable limit would be?


The limit is 27 disks total, it's imposed by the md system rather than RAID-6; RAID-6's inherent limit is 254+2 (see, again, the paper.)


	-hpa
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