Look in the pjsua API, there's method to register and unregister an account without using pjsua_acc_add.
Best regards,
Even Andr?
On 18. mai 2011, at 14.13, Laxman Pandey wrote:
> Dear Sir,
> I would like to register and unregister same sip account and it must not be crash. It is crashes third time.
> Sir i don't have idea how to use same account id and only add it with pjsua_acc_add once.
> pjsua_acc_add returns different reg id like 2 ,3, and next time it get crashes.
>
>
> Registring process:
>
> Step -1:
> regid = general_call_register(ACCOUNT_SIP,
> [[dict objectForKey:SIP_DOMAIN_KEY]UTF8String],
> [[dict objectForKey:SIP_USERNAME_KEY]UTF8String],
> [[dict objectForKey:SIP_PASSWORD_KEY]UTF8String],
> "*", [[dict objectForKey:SIP_PROXY_SRV_KEY] UTF8String]);
>
>
>
> Step -2: -int general_call_register(enum general_call_protocol calltype, const char *host, const char* user, const char *pass, const char* realm, const char* proxyserver )
> {
> int regid = -1;
>
>
> regid = pjsip_regist_account(user, pass, host, realm, proxyserver);
>
> if(regid != -1) add_new_register_acc(calltype, regid, user, pass, host, realm);
> return regid;
> }
>
>
> Step -3:
> int pjsip_regist_account(const char* sip_user, const char* sip_passwd, const char* sip_domain, const char* sip_realm, const char* proxyserver)
> {
> pjsua_acc_config acc_cfg;
> pj_status_t status;
> char buf[256];
> char buf2[256];
> int accid;
> static int count=1;//updated
>
> pjsua_acc_config_default(&acc_cfg);
> sprintf(buf,"sip:%s@%s", sip_user, sip_domain);
> acc_cfg.id = pj_str(buf);
> sprintf(buf2,"sip:%s", sip_domain);
> acc_cfg.reg_uri = pj_str(buf2);
> acc_cfg.cred_count = 1;
> acc_cfg.cred_info[0].scheme = pj_str("Digest");
> acc_cfg.cred_info[0].realm = pj_str(sip_realm);
> acc_cfg.cred_info[0].username = pj_str(sip_user);
> acc_cfg.cred_info[0].data_type = 0;
> acc_cfg.cred_info[0].data = pj_str(sip_passwd);
> if(proxyserver!=NULL && proxyserver[0] != '\0')
> acc_cfg.proxy[acc_cfg.proxy_cnt++] = pj_str(proxyserver);
>
> if (count==1) {//updated if condition for first time execution
> status = pjsua_acc_add(&acc_cfg,PJ_TRUE, &accid);
> count++;
> }
>
> if (status != PJ_SUCCESS) {
> pjsua_perror(THIS_FILE, "Error adding new account", status);
> return -1;
> }
> return accid;//Second time returns -1 and not register
> }
>
>
>
> - If i call pjsua_acc_add only once Then it gets register but second time it's not registering.
>
> Please help me.
>
>
> Thanks & Regards
> Laxman Pandey
>
>
> Message: 2
> Date: Tue, 17 May 2011 21:05:39 +0200
> From: Even Andr? Fiskvik <eaf@xxxxxxxxxx>
> To: pjsip list <pjsip at lists.pjsip.org>
> Subject: Re: iphone crashes when registering and unregistering
> account
> Message-ID: <34D4E059-D11E-4A21-8FB0-0DF4499C93C9 at oyatel.com>
> Content-Type: text/plain; charset=windows-1252
>
> If I understand you correctly you are adding the same account multiple times.
> This is the same as adding three different accounts, and I think there is an adjustable limit
> set somewhere on how many accounts you can use.
>
> What you are probably trying to achieve though is to unregister and register the same account,
> and for those cases you should use the same account ID and only add it with pjsua_acc_add ONCE.
>
> Best regards,
> Even Andr?
>
> On 17. mai 2011, at 16.22, Laxman Pandey wrote:
>
> > Dear Sir,
> >
> > When i try to register correct sip info.
> >
> > 1- it get register and return the reg id =2 from general_call_register();
> > then successfully unregister.
> >
> > 2- it get register and return the reg id =3 from general_call_register();
> > then successfully unregister.
> >
> > In third attempt it gets crash the application at the function-: status = pjsua_acc_add(&acc_cfg, PJ_TRUE, &accid);
> >
> > GDB Display:
> >
> > Current language: auto; currently c
> > Assertion failed: (pjsua_var.acc_cnt < (sizeof(pjsua_var.acc)/sizeof(pjsua_var.acc[0]))), function pjsua_acc_add, file ../src/pjsua-lib/pjsua_acc.c, line 290.
> > Program received signal: ?SIGABRT?.
> >
> > Could you please help me to solve this issue, I will be greatly thankful for the help.
> >
> > Regards
> > Laxman Pandey _______________________________________________
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>
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