On 23 June 2013 21:37, Ethan Rosenberg, PhD
<erosenberg@xxxxxxxxxxxxxxxxxxxx> wrote:
On 6/23/2013 2:31 PM, Ethan Rosenberg, PhD wrote:
Dear List -
There is an error in my query, and I cannot find it.
This fails:
$_SESSION['Cust_Num'] = $_REQUEST['cnum'];
$_SESSION['CustNum'] = $_REQUEST['cnum'];
echo "session<br />"; //this has the proper values
print_r($_SESSION);
$sql10 = "select Balance, Payments, Charges, Date from Charges
where
Cust_Num = $_SESSION[Cust_Num] order by Date";
echo $sql10; //echos the correct query
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
Against my better judgement, here I go again.
Is this the "actual" code you executed, or is it once again a typeover?
Your 1st error is in these two lines:
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
Yes your dump returns null. And always will.
Any further errors might be related to your non-standard syntax for
the session variable. Per the manual, associative arrays using string
indices should always use ' ' around them. They work (as mentioned in
the manual) but are wrong.
=======
Jim -
Is this the "actual" code you executed, or is it once again a typeover?
The actual code
Any further errors might be related to your non-standard syntax for
the session variable. Per the manual, associative arrays using string
indices should always use ' ' around them. They work (as mentioned in
the manual) but are wrong.
Newbie is confused.
Please explain.
Try ...
$sql10 = "select Balance, Payments, Charges, Date from Charges where
Cust_Num = {$_SESSION['Cust_Num']} order by Date";
--
Richard Quadling
Twitter : @RQuadling
EE : http://e-e.com/M_248814.html
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=========
Tried it. No luck
Ethan
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