On Jul 25, 2012, at 5:21 AM, Tamara Temple wrote:
Brad <nyctelecomm@xxxxxxxxx> wrote:
Here is where everything stands.. L
http://pastie.org/4317155
I feel strange bottom posting, somehow, BUT THAT'S THE RULE
You have never actually shown what your SQL statement is, because:
line 33: echo '$sql';
This will NOT interpolate the sql string. This is why you keep
getting:
line 57: array(1) { ["file"]=> array(5) { ["name"]=> string(14)
"emailsTest.txt" ["type"]=> string(10) "text/plain" ["tmp_name"]=>
string(14) "/tmp/phpcLtE6W" ["error"]=> int(0) ["size"]=>
int(61) } } $sqlYou have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ''\' LINES TERMINATED BY "\r\n" IGNORE 1 LINES'
at line 3
See where it says "$sqlYou have" after your vardump of $_FILES?
Change:
Line 33 to:
echo $sql.PHP_EOL;
then give it a go.
(The actual source of your problem is elsewhere, but I'll let you go
from there.)
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$sql = "BLAH BLAH BLAH var='".mysql_real_escape_string($var)."' LINES
TERMINATED BY '\r\n' IGNORE 1 LINES";
Strings for SQL are wrapped in single quotes and dont escape your
single quotes, the php $sql string is wrapped in double quotes.
HTH,
Best,
Karl DeSaulniers
Design Drumm
http://designdrumm.com
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