On 25 August 2011 14:07, Jim Giner <jim.giner@xxxxxxxxxxxxxxxxxx> wrote:
> First glance: your 'if' needs '= =' not '='
No.
Fully ...
if (False !== ($stmt = $dbObj->prepare(...))) {
...
}
In PHP, assignments evaluate to the value assigned.
If the value assigned can be evaluated as TRUE then the above test will pass.
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Richard Quadling
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