At 06:08 AM 11/2/2010, Artur Ejsmont wrote:
"Return Values
If only two parameters were passed to this function, the values parsed
will be returned as an array. Otherwise, if optional parameters are
passed, the function will return the number of assigned values. The
optional parameters must be passed by reference."
so you should expect an array. print_r it to see what is inside.
art
On 2 November 2010 03:34, Ethan Rosenberg <ethros@xxxxxxxxxxxxx> wrote:
> Dear List -
>
> Thank you for all your help. Here is another one.....
>
> I have a file [/home/ethan/PHP/RecNum] which consists of the number 1005.
> It also has been "1005". No matter how I do it, it is only recognized as
> 1.
>
> Here is the code. In this case, the file is "1005".
>
> $fptr1 = fopen("/home/ethan/PHP/RecNum", "r+");
> $recNum = (int)fscanf($fptr1,"%s");
> echo $recNum; //which always is 1
>
> If I do not typecast $recNum to int, the value is Array.
>
> Thanks.
>
> Ethan
>
> MySQL 5.1 PHP 5 Linux [Debian (sid)]
>
>
==============
Artur -
Thanks.
I also wanted to be able to increment recNum.
Her is what finally worked for me:
$fptr1 = fopen("/home/ethan/PHP/RecNum", "r+");
$recNum = fscanf($fptr1,"%d");
$sql1 = "insert into intake2 (Site,Record,BMI) values ('A',$recNum[0],19)";
$recNum[0] = $recNum[0] + 1;
rewind($fptr1);
fprintf($fptr1,"%d", $recNum[0]);
Ethan
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