Re: Mysql query

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ron.piggott@xxxxxxxxxxxxxxxxxx wrote:
The query from my previous post was only part of a larger query.  This is
the entire query:

SELECT GREATEST( IF( CURDATE( ) >= DATE_SUB( DATE( FROM_UNIXTIME(
1239508800 ) ) , INTERVAL LEAST( 14, (

SELECT COUNT( * )
FROM `verse_of_the_day_Bible_verses`
WHERE seasonal_use =1 ) )
DAY )
AND CURDATE( ) <= DATE( FROM_UNIXTIME( 1239508800 ) ) , 1, 0 ) , IF(
CURDATE( ) >= DATE_SUB( DATE( 2009 -12 -25 ) , INTERVAL LEAST( 14, (

SELECT COUNT( * )
FROM `verse_of_the_day_Bible_verses`
WHERE seasonal_use =2 ) )
DAY )
AND CURDATE( ) <= DATE( 2009 -12 -25 ) , 2, 0
)
) AS verse_application

It took me a while to work out what this was trying to do, that's complicated.

Reformatted a little:

SELECT
  GREATEST(
    IF
	(
      CURDATE() >=
	    DATE_SUB(
		    DATE(FROM_UNIXTIME(1239508800)),
		    INTERVAL LEAST(14, (SELECT 1)) DAY)
	  AND CURDATE() <= DATE(FROM_UNIXTIME(1239508800)),
      1,
      0
	),
    IF
	(
	  CURDATE() >=
	    DATE_SUB(
		  DATE('2009-12-25'),
		  INTERVAL LEAST(14, (SELECT 2)) DAY)
      AND CURDATE() <= DATE('2009-12-25'),
	  2,
	  0
    )
  ) AS verse_application;

(which isn't much better in email).

You're not getting '2' because the second part is returning 0.

I substituted dummy variables for your subqueries (select 1 and select 2).

SELECT COUNT( * )
FROM `verse_of_the_day_Bible_verses`
WHERE seasonal_use =2;

What does that return by itself?

that is what your query will run instead of my 'select 2'.

That in turn goes into the

select least(14, result_from_above_query);

and takes that away from date('2009-12-25');

If the current date is not in that range, it will return 0.

Here's the second part of your query isolated for you to test:

SELECT
  IF
    (
      CURDATE() >=
        DATE_SUB(
          DATE('2009-12-25'),
INTERVAL LEAST(14, (SELECT COUNT(*) FROM verse_of_the_day_Bible_verses WHERE seasonal_use=2)) DAY)
        AND CURDATE() <= DATE('2009-12-25'),
    2,
    0
  )
;


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