2009/7/22 Bilal Ahmad <engg.bilalmalik@xxxxxxxxxxxxxx>:
> Hi All, I wanna ask a question pleasenV. I am trying to create an image on
> fly, please do help me , following is the code.
>
> *File Name : Font.php
> Code: *
>
> <html>
> <head>
> <title>Image Creation</title>
>
> <script language="javascript">
> var xmlhttp;
>
> function showPic()
> {
> xmlhttp=GetXmlHttpObject();
> if (xmlhttp==null)
> {
> alert ("Browser does not support HTTP Request");
> return;
> }
>
> var text = document.getElementById("textfield").value;
>
> var url="image.php";
> url=url+"?text="text;
> alert(url);
> url=url+"&sid="+Math.random();
> xmlhttp.onreadystatechange=stateChanged;
> xmlhttp.open("GET",url,true);
> xmlhttp.send(null);
> }
>
> function stateChanged()
> {
> if (xmlhttp.readyState==4)
> {
> if(xmlhttp.responseText == 1)
> {
> document.getElementById("pic").style.display="block";
> }
> }
> }
>
> function GetXmlHttpObject()
> {
> if (window.XMLHttpRequest)
> {
> // code for IE7+, Firefox, Chrome, Opera, Safari
> return new XMLHttpRequest();
> }
> if (window.ActiveXObject)
> {
> // code for IE6, IE5
> return new ActiveXObject("Microsoft.XMLHTTP");
> }
> return null;
> }
> </script>
> </head>
> <body>
> <form name="form1" method="post" action="" onSubmit=" return false;">
> <table width="304" border="1">
> <tr>
> <td colspan="2"><div align="center">Text</div></td>
> </tr>
> <tr>
> <td>Text</td>
> <td><label>
> <input type="text" name="textfield" id="textfield">
> </label></td>
> </tr>
> <tr>
> <td colspan="2"><label>
> <div align="center">
> <input type="submit" name="button" id="button" value="Update"
> onClick="showPic()">
> </div>
> </label></td>
> </tr>
> <tr>
> <td colspan="2"><div id="pic" style="display:none"><img src="pic.jpg"
> /></div></td>
> </tr>
> </table>
> </form>
> </body>
> </html>
>
> *File Name : image.php
> Code:*
>
> [php]
>
> $name = $_GET['text'];
>
> $pic = imagecreatetruecolor(100, 100);
> $text_color = imagecolorallocate($pic, 255, 255, 255);
> imagestring($pic, 10, 15, 15, $name, $text_color);
> $pi = Imagejpeg($pic,"pic.jpg");
> echo $pi;
> ImageDestroy($pic);
>
> [/php]
>
> *Problem: *
>
> What this code is doing is that, it creates a new image with the text (that
> user enters) on it, but loads the image that was created previously, I want
> that it should display the text on the picture which users enter on the fly.
> ( e.g. If user enter TEXT as text it should display TEXT on the picture
> displayed, soon after we get response from ajax).I hope you got the problem.
>
>
> Thanks
>
Try changing ...
$pi = Imagejpeg($pic,"pic.jpg");
echo $pi;
to ...
imagejpeg($pic);
--
-----
Richard Quadling
Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
"Standing on the shoulders of some very clever giants!"
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