Re: Postgres query failing, not enough info for debugging...

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Jason Gerfen wrote:
Carol Walter wrote:
Hello,

I'm using PHP 5 and PostgreSQL 8.3.6. I have a query that is failing and I don't know how to troubleshoot the problem. The error message that it is giving is quite vague. The error message is as follows:


Warning: pg_query_params() [function.pg-query-params]: Query failed: ERROR: syntax error at end of input at character 156 in /home/walterc/ssl/PHP/km_input_test2c.php on line 631
ERROR: syntax error at end of input at character 156

The query that is failing looks like this...

$pg_pres_ins6 = pg_query_params("INSERT INTO \"brdgMediaCallsEvents\" (\"mediumId\", \"eventId\", rank) VALUES ((currval('\"tblMedia_mediumId_seq\"'), (currval('\"tblCallsEvents_eventId_seq\"'), $1)", array($ev_rank));
 echo pg_last_error($pg_connection);


Whoops, ignore the last one I forget a single quote after the actual sql string

Perhaps try:
$pg_pres_ins6 = pg_query_params( $pg_connection, 'INSERT INTO `brdgMediaCallEvents` ( `mediumId`, `eventId`, `rank` ) VALUES ( \"val1\", \"val2\", \"val3\" )', array( "ev_rank" ) );

You need to read the document for this function because it looks like you were mis-using it.

http://us3.php.net/manual/en/function.pg-query-params.php


It's quite possible this is something very simple and I'm just not seeing it. I commented out this query because I thought perhaps it was failing because it was the last query in the program. The previous query did not fail when it became the last one.

Thanks in advance for your help.

Carol




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Jason Gerfen
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