SELECT LIKE with "%" and without "%"

["Emiliano Boragina" <emiliano.boragina@xxxxxxxxx>]

Hello.

I am using this:
$sql = "SELECT * FROM table WHERE ID LIKE '%$_GET[id]%' AND title LIKE
'%$_GET[word]%'";

But I want exactlu ID, not one part of many possibles Ids in the DB.
How can I do that?

Thanks

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   // Emiliano Boragina _
   // Diseño & Comunicación //////////////////
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   // emiliano.boragina@xxxxxxxxx  /
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