Thanks Martin, oddly enough that still doesn't pull any results, it won't even print the variables if I try to list them to see, I know my db connection is good checked that, and can do really simple queries, would something be preventing a JOIN from working? When I Reveal my variables this query snippet: $sql = "SELECT admin.AdminID, workorders.WorkOrderID FROM admin INNER JOIN workorders ON admin.AdminID=workorders.AdminID HAVING admin.username='".$_SESSION['user']."' "; $result2 = mysql_query ($sql); $row2 = mysql_fetch_assoc ($result2); $Total = ceil(mysql_num_rows($result2)/$PerPage); Returns this: $sql"SELECT admin.AdminID, workorders.WorkOrderID FROM admin INNER JOIN workorders ON admin.AdminID=workorders.AdminID HAVING admin.username='tmiller' "$result2""$row2"" Terion On Thu, Jan 29, 2009 at 11:56 AM, Martin Zvarík <mzvarik@xxxxxxxxx> wrote: > This will work: > > $sql = " > SELECT admin.AdminID, workorders.WHAT_YOU_WANT > FROM admin > INNER JOIN workorders ON admin.AdminID=workorders.AdminID > HAVING admin.username='".$_SESSION['user']."' > "; > > > Terion Miller napsal(a): > > Hi Everyone! I am having problems getting an INNER JOIN to work and need >> some tips trouble shooting where the problem may be. >> >> What I'm trying to do is match up AdminID's from two tables and display >> only >> that users orders, sounds simple enough right...but I can't get it to >> return >> the AdminID... >> >> My Query: >> >> $sql = >> "SELECT admin.AdminID , workorders.AdminID >> FROM admin >> INNER JOIN >> workorders ON >> (admin.AdminID=workorders.AdminID) >> WHERE admin.UserName = '".$_SESSION['user']."' "; >> >> >> $result = mysql_query ($sql); >> $row = mysql_fetch_assoc ($result); >> $Total = ceil(mysql_num_rows($result)/$PerPage); >> >> Thanks for any tips on how else I can accomplish this... >> Terion >> >> > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >