Re: Probleme with MySQL queries

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You have to pass mysql_num_rows a $result variable from your query.

Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com



David DURIEUX wrote:
> Bonjour,
>
>
>
> Cordialement,
>
> David DURIEUX
> Tel : 04.74.04.81.34
> Port : 06.34.99.45.18
> Mail : d.durieux@xxxxxxxxxxxxx
> Site Web : http://www.siprossii.com/
>
> SIPROSSII
> 847 route de Frans (Créacité)
> 69400 Villefranche sur Saône
>
> ID is INT. It's ok before.
>
> I have errors : 
>
>
> Warning: Wrong parameter count for mysql_num_rows()
> in /usr/home/sites/CL000001/Web_data/hebergement/pages/sousdomaines.php
> on line 7 string(0) "" NULL
>
> Warning: Wrong parameter count for mysql_num_rows()
> in /usr/home/sites/CL000001/Web_data/hebergement/pages/sousdomaines.php
> on line 12 string(0) "" NULL
>
> Warning: Wrong parameter count for mysql_num_rows()
> in /usr/home/sites/CL000001/Web_data/hebergement/pages/sousdomaines.php
> on line 16 string(0) "" NULL 
>
>
>
> Le Wed, 3 Sep 2008 12:11:00 +0200
> "Evert Lammerts" <evert.lammerts@xxxxxxxxx> a écrit:
>
>   
>>> In fact the first return 0 results
>>>       
>> So the problem is in your select, and if your select works when you
>> manually insert the value for id (iow, without using $var), the
>> problem has something to do with $var.
>>
>> Is the data type of the ID column INT? Try the following and let us
>> know the output:
>>
>> $var=107;
>> $query = mysql_query("SELECT * FROM table WHERE id={$var};") or
>> die(mysql_error()); // make sure to use double quotes
>> var_dump(mysql_error(), mysql_num_rows());
>>
>> $var=mysql_real_escape_string("107");
>> $query = mysql_query("SELECT * FROM table WHERE id={$var};") or
>> die(mysql_error()); // make sure to use double quotes
>> var_dump(mysql_error(), mysql_num_rows());
>>
>> $query = mysql_query("SELECT * FROM table WHERE id=107;") or
>> die(mysql_error()); // make sure to use double quotes
>> var_dump(mysql_error(), mysql_num_rows());
>>
>>     
>
>
>   

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