I am trying to fetch the image from the database image field. Fetching it from $image=mysql_result($result,$i,"image"); And displaying it with: ../stores-images/ I know it requires some if else or array to display. This is new for me. Please help! Chris -- View this message in context: http://www.nabble.com/Is-displaying-image-in-php-tough--tf4607902.html#a13158056 Sent from the Php - Database mailing list archive at Nabble.com. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
