Re: Store more than 1 piece of information in a single variable

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First.. You're using mysql_fetch_array when you wanted
mysql_fetch_assoc.. .. select user_id from whatever .. and then $row =
mysql_fetch_array($res) .. youd have a $row[0].. mysql_fetch_assoc
would allow $row['user_id']

Secondly.. You can use one query to select all the info..

select e107.user_id FROM db2.e107_user as e107 left join
db1.clanmembers as clan on e107.user_loginname = clan.user_loginname

You'll still want to mysql_select_db($db2) for your insert query

Thirdly.. I'd change the insert query to:

$user_id = mysql_real_escape_string($user_id);
$query = "INSERT INTO e107_private_msg VALUES (NULL, '1', '$user_id',
NOW(), '0', 'Clan War 2', 'Clan War Arranged', '0', '0', '', '+rr+',
'0')";
mysql_query($query) or die('Query 3 failed. ' . mysql_error());

Where the entire query is surrounded by double quotes, so you dont
have to back slash singles.. $user_id is escaped, so its safe.. using
mysql's NOW() function instead of php's time()..

On 8/3/07, Arena Servers <smithster@xxxxxxxxxxxxxxxxxxxx> wrote:
> mysql_select_db($db_name2);
>
> $query = "SELECT user_id FROM `e107_user` WHERE `user_loginname` = '$user_loginname'";
>
> $result = mysql_query($query) or die('Query 2 failed. ' . mysql_error());
>
> while ($row = mysql_fetch_array($result)){
>
> $user_id = ($row['user_id']);
>
> $query = 'INSERT INTO e107_private_msg VALUES (NULL, \'1\', \''.$user_id.'\', \''.$time.'\', \'0\', \'Clan War 2\', \'Clan War Arranged\', \'0\', \'0\', \'\', \'+rr+\', \'0\');';
>
> $result = mysql_query($query) or die('Query 3 failed. ' . mysql_error());
>
> }

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