Chris Carter wrote:
I have a field in database called "logos" which has one value "images/logos/some_logo.jpg" In my php I am trying to call it in my php file as image. With this code. $sno = $_REQUEST['sno']; $query="SELECT logos FROM table WHERE sno = '$sno'";
Please please please read http://www.phpsec.org/ particularly http://phpsec.org/projects/guide/3.html#3.2 -- Postgresql & php tutorials http://www.designmagick.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
