I'm using PHP 5, I'm running this off of my personal laptop so I downloaded
ApacheTriad2
----- Original Message -----
From: "Stephen Johnson" <maillists@xxxxxxxxxxxxxxxx>
To: "Alexander" <kurokawa@xxxxxxx>; "PHP-DB" <php-db@xxxxxxxxxxxxx>
Sent: Saturday, January 27, 2007 8:24 PM
Subject: Re: Am I missing something?
What version of php are using? It is odd that mysql_real_escape_string is
undefined..
Alternately you could addslashes...
Hope this helps
<?php
/*
Stephen Johnson c | eh
The Lone Coder
http://www.ouradoptionblog.com
Join our journey of adoption
http://www.thelonecoder.com
stephen@xxxxxxxxxxxxxxxx
continuing the struggle against bad code
*/
?>
From: Alexander <kurokawa@xxxxxxx>
Date: Sat, 27 Jan 2007 20:17:54 -0600
To: PHP-DB <php-db@xxxxxxxxxxxxx>
Subject: Re: Am I missing something?
Alright, this may be the problem:
Fatal error: Call to undefined function mysql_real_escape_string() in
C:\apache2triad\htdocs\gallery.php on line 10
which is refering to :
$picture = mysql_real_escape_string($picture);
/* never again use direct code from an example in a book, there's always
an
error */
----- Original Message -----
From: "Alexander" <kurokawa@xxxxxxx>
To: "PHP-DB" <php-db@xxxxxxxxxxxxx>
Sent: Saturday, January 27, 2007 8:13 PM
Subject: Re: Am I missing something?
No change.
I echod my insert statement and got : INSERT INTO domains ( picture,
thumbnail ) values( "$picture", "$thumbnail" )
excatly like that. Shouldn't the values echo as what should be inserted
into the database?
----- Original Message -----
From: "Stephen Johnson" <maillists@xxxxxxxxxxxxxxxx>
To: "Alexander" <kurokawa@xxxxxxx>; "PHP-DB" <php-db@xxxxxxxxxxxxx>
Sent: Saturday, January 27, 2007 8:01 PM
Subject: Re: Am I missing something?
My first thought is that your values in your insert statement are not
in
quotes..
$insert = 'INSERT INTO domains ( picture, thumbnail ) values(
$picture, $thumbnail )';
Should be
$insert = 'INSERT INTO domains ( picture, thumbnail ) values(
"$picture",
"$thumbnail")';
Hope that helps.
<?php
/*
Stephen Johnson c | eh
The Lone Coder
http://www.ouradoptionblog.com
Join our journey of adoption
http://www.thelonecoder.com
stephen@xxxxxxxxxxxxxxxx
continuing the struggle against bad code
*/
?>
From: Alexander <kurokawa@xxxxxxx>
Date: Sat, 27 Jan 2007 19:55:17 -0600
To: PHP-DB <php-db@xxxxxxxxxxxxx>
Subject: Am I missing something?
I fixed my code and it shows up fine now. It says it supposedly enters
the
data when I input the fields but when I check the MySQL database, the
info
isn't there.
Here's the fixed code if you wish to test it:
<html>
<body>
<?php
function add_to_table( $picture, $thumbnail ) {
$picture = mysql_real_escape_string($picture);
$thumbnail = mysql_real_escape_string($thumbnail);
$user = "user";
$pass = "password";
$database = "mydata";
$link = mysql_connect("localhost", $user, $pass);
if(!$link) {
echo 'Error in linking';
}
$db = mysql_select_db($database, $link);
$insert = 'INSERT INTO domains ( picture, thumbnail ) values(
$picture, $thumbnail )';
$indata = mysql_query( $insert, $link );
}
function write_form() {
echo "<form method='post' action='{$_SERVER['PHP_SELF']}'>";
echo "<p>Enter url of large picture: <input type='text'
name='picture' />";
echo "<p>Enter url of thumbnail: <input type='text'
name='thumbnail' />";
echo "<p><input type='submit' value='Add to Database' />";
echo "</form>";
}
if ( !empty( $_REQUEST['picture'] ) && !empty(
$_REQUEST['thumbnail'] ) ) {
$input = add_to_table( $_REQUEST['picture'],
$_REQUEST['thumbnail'] );
if(!input) {
echo 'Error\!';
}
else {
echo 'Data enter successfully\!';
$idreturn = mysql_insert_id($input);
echo 'Image inserted to ID ' . $idreturn;
}
}
else {
write_form();
}
?>
</body>
</html>
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