No, it shouldn't because there are only two B's, one is followed by a
'v' (one of your exceptions) and the other is at the end of the line, right?
-Micah
Mike van Hoof wrote:
That is it almost :)
SELECT 'oer bv b' REGEXP 'b[^v]$|b[^v]\s?';
gives me 0 as a result, while it shoud give me 1, because there is a b
in there which is not bv.
Mike
Medusa, Media Usage Advice B.V.
Science Park Eindhoven 5216
5692 EG SON
tel: 040-24 57 024 fax: 040-29 63 567
url: www.medusa.nl
mail: mike@xxxxxxxxx
Uw bedrijf voor Multimedia op Maat
Micah Stevens schreef:
Your code states:
Match: one of the following letters: -,b,|,^,b negative look ahead
one of these: -,v,$,|,v
Which isn't what you're looking for. Remember the negating '^' only
works at the start of a [] list. And '$' only means line-end if it's
outside [], inside it stands for the '$' character.
I think this would work better:
b[^v]$|b[^v]\s?
HTH,
-Micah
mike@xxxxxxxxxxxxxxxx wrote:
Hello,
i am try to make a regular expression work, but keep getting an
error message
does anyone know how i can make it work?
The query is:
SELECT 'boer bv' REGEXP '[ b|^b](?![v$|v ])';
So it has to match each starting 'b' and all the b's pf following
words. But now followed by a v(line end) or a v followed by a space.
so it should match:
'b test'
'test b'
'test b bv'
'bv b test'
and NOT
'test bv'
'bv test'
Any idea's?!
Thanks, mike
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