Re: Syntax Error

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JD wrote:
Can anyone help me figure out what is wrong with this syntax.  Thanks.

list($qh,$num) = dbQuery("SELECT password AS passwd1, $DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 ".

"FROM $USER_TABLE WHERE username='$username'");

$data = dbResult($qh);


No need to repost your question.

What is the $DATABASE_PASSWORD_FUNCTION variable ?

What is the $USER_TABLE variable ?

Since there are 4 variables in this query ($DATABASE_PASSWORD_FUNCTION, $password, $USER_TABLE, $username), we have no idea what's actually being run.

The easiest way to work out what's wrong is to print the query out and run it manually.

$query = "SELECT password AS passwd1, $DATABASE_PASSWORD_FUNCTION('$password') AS passwd2 FROM $USER_TABLE WHERE username='$username'";

echo wordwrap($query) . "<br/>\n";

list ($qh, $num) = dbQuery($query);

....

Post us the real sql query that's being run through that and we might be able to help you.

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