Peter Beckman wrote:
> if (($row = mysql_fetch_row($result))[3] == 'foo') {
> $user = $row;
> }
>
> or
>
> $bar = explode('#', $str)[2];
PHP does not currently support this type of syntax in any form. You must
assign the return value of a function to a variable if you want to
access it as an array.
-Stut
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