Ron Piggott (PHP) wrote:
I have a web form that accepts up to 3 suggested categories. In the
form they are part of I have named these variables
$suggested_category_1
$suggested_category_2
$suggested_category_3
I have come up with this simple code to store the suggestion in a table:
if ( $suggested_category_1 <> "" ) {
#the user could leave the suggestion blank because what is already
provided is sufficient
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO table_name VALUES ( '$variable' ,
'$reference_number', '$suggested_category_1')";
mysql_query($query);
mysql_close();
}
Is there any way to create a loop to check all three instead of me
repeating this code twice more changing $suggested_category_1 to _2 and
_3 ?
for ($num = 1; $num <= 3; $num++)
{
$varname = 'suggested_category_'.$num;
$val = $$varname;
// Stick your code here replacing references to the
$suggested_category_1 var with $val
}
Incidentally, I do hope that code was simplified for brevity. There
should be extensive use of mysql_real_escape_string in there.
-Stut
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