Hi Anna:
I feel kinda stupid, asking the same thing more than
twice, but should i add:
<?php
Header("Content-type:application/x-www-urlform-encoded");
?>
On the php script? or on the as code of the
animation??
Thanks for the patience and the help.
Juan.
--- annA <escape2ocean@xxxxxxxxx> escribió:
Hi Juan,
Micah is correct. You must try it in the Flash
environment.
As I was lazy and didn't want to check all your php,
I created a simple
test file from your mail:
<?php Header("Content-type:
application/x-www-urlform-encoded");?>
n=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Destinatario0=martan=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Receptor0=marilun=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Destinatario0=martan=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian
Flash read it & seemed to parse the variables just
fine. That indicates
that your php output is well-formed from the Flash
point of view - well
in the example given anyway! ;)
If, after adding the header, you still have problems
reading in the data
in the example then the problem is more likely in
the actionscript.
hth,
anna
---------------------------------------------------------------------------
Micah Stevens wrote:
Yes, that sounds correct, when flash requests the
page directly, it will
realize it's URLEncoded (or should) and read the
variables correctly.
Your browser on the other hand isn't built to
display this information,
so it
wants you to tell it where to save it.
-Micah
On Tuesday 04 October 2005 9:43 am, Juan Stiller
wrote:
> Hi anna,
>
> Thanks for the suggestion, but it didn't worked,
when
> i try it on the browser, it ask me if i want to
> download , open the file.
>
> Any other sugg........?
>
> --- annA <escape2ocean@xxxxxxxxx> escribi�:
> > Hi Juan,
> >
> > I haven't read the list for a 'few' days so I'm
> > sorry if you've been
> > sweating over this, but if you haven't yet
solved it
> > then make sure you
> > send a
> >
> > Header("Content-type:
> > application/x-www-urlform-encoded");
> >
> > before your
> >
> > echo $rString;
> >
> > annA
>
>
---------------------------------------------------------------------------
>-
>
> > Subject:
> > Showing various result from a mysql query
> > From:
> > Juan Stiller <juanstiller@xxxxxxxxxxxx>
> > Date:
> > Thu, 29 Sep 2005 20:11:27 +0000 (GMT)
> > To:
> > php-db@xxxxxxxxxxxxx
> >
> > Hi, im working on a php file that its supposed
to
> > retrieve data from a mysql database, to send it
to a
> > flash animation to show the results. Thing is
that
> > im
> > testing some modifications to the code, so if
there
> > is
> > more than one entry, it shows all the results.
> >
> > For some reason probably a mistake on the code
im
> > getting this output when i try the muestra.php
file
> > on
> > the browser:
>
>
n=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre
0=cristian&Destinatario0=martan=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Di
a0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Receptor0=marilun=1&Hora0=17:30:43&A
pellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=2005&Nombre0=cristian&Destinatar
io0=martan=1&Hora0=17:30:43&Apellido0=garofalo&Id0=6&Dia0=28&Mes0=9&Ano0=200
>5&Nombre0=cristian
>
> > This might not be wrong, but when i show info
on the
> > flash animation i get eg:
> >
> > Apellido0=garofalo , i dont want to get the n=x
on
> > the
> > output, its supposed to be just an internal
thing to
> > tell flash that for the variable
Apellido(lastname)
> > there is more than one result and then to show
all
> > of
> > them.
> >
> >
> > This is the php code:
> >
> > <?php
> > $conn = @mysql_connect("localhost", "blah",
> > "blah23");
> >
> > if (!$conn) {
> > echo( "<P>No se pudo conectar " .
> > "al servidor MySQL.</P>" );
> > exit();
> > }
> >
> > if (! @mysql_select_db("llamadas") ) {
> > echo( "<P>No se puede encontrar " .
> > "la base de datos clientes!</P>" );
> > exit();
> > }
> >
> > $qr = mysql_query("select * from datos");
> > $nrows =
> > mysql_num_rows($qr);
> > $rString = "n=".$nrows;
> > for ($i=0; $i < $nrows; $i++) {
> > $row = mysql_fetch_array($qr);
> > $rstring .= "&Id".$i."=".$row['id'];
> > $rString .=
>
>
"&Dia".$i."=".$row['dia']."&Mes".$i."=".$row['mes']."&Ano".$i."=".$row['ano
>'];
>
> > $rString .=
>
>
"&Hora".$i."=".$row['hora']."&Minutos".$i."=".$row['minutos'];
>
> > $rString .=
"&Receptor".$i."=".$row['receptor'].
> > $rString .=
> > "&Destinatario".$i."=".$row['destinatario'].
> > $rString .=
"&Apellido".$i."=".$row['apellido'].
> > $rstring .= "&Nombre".$i."=".$row['nombre'];
> > $rstring .=
"&Telefono".$i."=".$row['telefono'];
> > $rstring .= "&Asunto".$i."=".$row['asunto'];
> > }
> > echo $rString;
> > mysql_free_result($qr);
> > ?>
> >
> > Also, i was told that including password and
user to
> > connect to mysql server sholdn´t be shown on
the php
> > file, so i have to use include_one and the
file, but
> > i
> > don´t know exaclty the syntax, can anybody
help me
> > with it?
> >
> > Thanks in advance.
>
>
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